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3 years ago

(08.01)

Mathematics

2 answers:

Serggg [28]3 years ago

6 0

Answer:

there are 114 seats in the 23rd row

Step-by-step explanation:

alexandr1967 [171]3 years ago

3 0

The given in the problem above is an arithmetic sequence with the first term equal to 4 and the common difference is 5. To determine the number of seats on row 23, use the formula,

an = a1 + (n - 1) d

Solving for the 23rd term,

an = 4 + (22) 5 = 114 seats

Therefore, the answer is there are 114 seats on the 23rd row.

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Help will mark brainiest

Kitty [74]

Answer:

original price =148.57

Step-by-step explanation:

The original price * discount is the markdown

original price - discount = sale price

original price - original price * discount = sale price

Factor out the original price

original price (1-discount) = sale price

We know the discount is 65% and the sale price is 52

original price (1-.65) = 52

original price (.35) = 52

Divide by .35 on each side

original price (.35)/.35 = 52/.35

original price =148.57

6 0

3 years ago

Read 2 more answers

If 1/4 of the 7th graders got an A on the test and 2/5 of them got a B, that fraction of the students got an A or B?

posledela

Answer: $\dfrac{13}{20}$

Step-by-step explanation:

Given: Fraction of 7th graders got A = $\dfrac14$

Fraction of 7th graders got B = $\dfrac25$

The fraction of the students got an A or B = Fraction of 7th graders got + Fraction of 7th graders got B

$=\dfrac14+\dfrac25\\\\=\dfrac{5+2(4)}{5\times4}\\\\=\dfrac{5+8}{20}\\\\=\dfrac{13}{20}$

Hence, the required fraction: $\dfrac{13}{20}$

5 0

3 years ago

Solve by quadratic equation

Ymorist [56]

<h2>Question :</h2>

$\tt \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}$

<h2>Answer :</h2>

$\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}$

<h2>Explanation :</h2>

$\tt : \implies \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}$

$\tt : \implies \dfrac{(x+2)(x+2) + (x-2)(x-2)}{(x-2)(x+2)} = \dfrac{5}{6}$

$\tt : \implies \dfrac{(x+2)^{2} + (x-2)^{2}}{(x-2)(x+2)} = \dfrac{5}{6}$

<u>Now, we know that</u> :

$\large \underline{\boxed{\bf{(a+b)^{2} = a^{2} + b^{2}+ 2ab}}}$
$\large \underline{\boxed{\bf{(a-b)^{2} = a^{2} + b^{2} - 2ab}}}$
$\large \underline{\boxed{\bf{(a+b)(a-b) = a^{2} - b^{2}}}}$

$\tt : \implies \dfrac{x^{2}+2^{2}+ 2 \times x \times 2 + x^{2}+2^{2} - 2 \times x \times 2 }{x^{2}-2^{2}} = \dfrac{5}{6}$

$\tt : \implies \dfrac{x^{2}+ 4 + \cancel{4x} + x^{2}+ 4 - \cancel{4x}}{x^{2}-4} = \dfrac{5}{6}$

$\tt : \implies \dfrac{x^{2} + x^{2} + 4 + 4}{x^{2}-4} = \dfrac{5}{6}$

$\tt : \implies \dfrac{2x^{2} + 8}{x^{2}-4} = \dfrac{5}{6}$

<u>By cross multiply</u> :

$\tt : \implies (2x^{2} + 8)6= 5(x^{2}-4)$

$\tt : \implies 12x^{2} + 48 = 5x^{2}-20$

$\tt : \implies 12x^{2} + 48 - 5x^{2} + 20 = 0$

$\tt : \implies 7x^{2} + 68 = 0$

$\tt : \implies 7x^{2} + 0x + 68 = 0$

<u>Now, by comparing with ax² + bx + c = 0, we have</u> :

a = 7
b = 0
c = 68

<u>By using quadratic formula</u> :

$\large \underline{\boxed{\bf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}}}$

$\tt : \implies x = \dfrac{-(0) \pm \sqrt{(0)^{2} - 4(7)(68)}}{2(7)}$

$\tt : \implies x = \dfrac{0 \pm \sqrt{0 - 1904}}{14}$

$\tt : \implies x = \dfrac{\pm \sqrt{- 1904}}{14}$

$\tt : \implies x = \dfrac{\pm \sqrt{2\times 2\times 2\times 2\times 7\times 17}}{14}$

$\tt : \implies x = \dfrac{\pm \cancel{2} \times 2\sqrt{7\times 17}}{\cancel{14}}$

$\tt : \implies x = \dfrac{\pm2\sqrt{119}}{7}$

$\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}$

Hence value of $\bf x =\dfrac{\pm 2\sqrt{119}}{7}$

5 0

3 years ago

Read 2 more answers

IS THE ANSWER B JUST TRYING TO CHECK

Yuki888 [10]

Answer:

No my dude its c

Step-by-step explanation:

3 0

3 years ago

Crowned Brainly and will have 10 points. EMERGENCY!

gavmur [86]

Answer:

324ft^2

Step-by-step explanation:

rectangle: 22ft X 12ft = 264ft^2

trapazoid: 1/2(22+8)4 = 60ft^2

264 + 60 = 324ft^2

hope this helped!! :D

tell me if you need further explaination!

3 0

3 years ago