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jeyben [28]
2 years ago
5

minute maid states that a bottle of juice contains 473 ml. consumer groups are interested in determining if the bottles contain

less than the amount stated on the label. to test their claim, they sample 30 bottles. the sample mean was 472ml and the standard deviation is 0.2. is minute maid putting less than 473 ml into the bottles? select the correct null and alternative hypothesis below.
Mathematics
1 answer:
zvonat [6]2 years ago
3 0

Answer:

The average juice a bottle contain is the mean value of the juice.

is the average content in all bottles of juice in the population, which is 472mL.

The given parameters are:

--- the sample size

--- the standard deviation

--- the sample mean

--- the population mean

The above highlights means that:

The parameter  represents the population mean

This means that:

is the average content in all bottles of juice in the population.

From the question, the value is given as: 473

Hence, the true statement is:

is the average content in all bottles of juice in the population, which is 473mL.

Step-by-step explanation:

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3 years ago
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Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =
swat32

Answer:

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Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

\bar{d} = \frac{\sum x-y}{n}

\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625

Standard deviation: SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1}  }

\sum d^{2}  = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2}  = 63

SD = \sqrt{\frac{63 - 8 *  (-0.625)^2}{8-1}  }

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Under the null hypothesis, the formula for the test statistics will be given by:

t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n}  } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8}  }

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