Question

Find 10th term of a geometric sequence whose first two terms are 2 and -8. Please answer!!

Answer 1

Answer:

The 10th term is -524,288

Step-by-step explanation:

The general format of a geometric sequence is:

$a_{n} = r*a_{n-1}$

In which r is the common ratio and $a_{n+1}$ is the previous term.

We can also use the following equation:

$a_{n} = a_{1}*r^{n-1}$

In which $a_{1}$ is the first term.

The common ratio of a geometric sequence is the division of the term $a_{n+1}$ by the term $a_{n}$

In this question:

$a_{1} = 2, a_{2} = -8, r = \frac{-8}{2} = -4$

10th term:

$a_{10} = 2*(-4)^{10-1} = -524288$

The 10th term is -524,288