Answer:
Area of the triangle = 32in^2
Area of rectangle = 144in^2
Area of rectangle without triangle = 112in^2
Answer:
2x +3y=1⇒equation 1
3x=2y+8
3x-2y=8⇒equation 2
by elimination method,
2x+3y=1 ×2
3x-2y=8 ×3
4x+6y=2
9x-6y=24
cut 6y and -6y
4x+6y=2
9x-6y=24
---------------
13x+0=26
13x=26
x=26/13
x=2
substitute x=2 in equation 1
2(2)+3y=1
4+3y=1
3y=1-4
3y=-3
y=-3/3
y=-1
therefore, x=2 and y=-1
hope it helps u!
Answer:
its is 192 I just took this assignment
The sum of all interior angles in a polygon is
180(n-2), where n = sides, well, this is a QUADrilateral, so it has 4 sides, so the total is 360°.
now, let's find what angle C is first,
![\bf \stackrel{A}{(2x-40)}+\stackrel{B}{(116)}+C+\stackrel{D}{(x)}=360\implies C+3x+76=360 \\\\\\ C+3x=284\implies C=284-3x](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7BA%7D%7B%282x-40%29%7D%2B%5Cstackrel%7BB%7D%7B%28116%29%7D%2BC%2B%5Cstackrel%7BD%7D%7B%28x%29%7D%3D360%5Cimplies%20C%2B3x%2B76%3D360%0A%5C%5C%5C%5C%5C%5C%0AC%2B3x%3D284%5Cimplies%20C%3D284-3x)
now, recall the "inscribed quadrilateral conjecture", where opposite angles are "supplementary angles", thus
the nearest ten would be 50, Just go up till the next 10,20,30,40,50,60,70.etc. all of them are by tens
40-44 is going down 45-49 is going up