4z+2(z-4)=3z+11 perform indicated multiplication on left side
4z+2z-8=3z+11 combine like terms on left side
6z/-8=3z+11 add 8 to both sides
6z=3z+19 subtract 3z from both sides
3z=19 divide both sides by 3
z=19/3
z=6 1/3
So there is only one solution when z=6 1/3
Answer:
4 she lost 4 pounds, how do u not know this dood
Step-by-step explanation:
Hello! I can help you! In general, the larger the size, the larger the cost. We will assume that $8 is the youth size and $12 is the adult size. x is the youth side and y is the adult side. The first part of the equation is 8x + 12y, BUT the key words in the problem are AT MOST, so out sign will be less than or equal to (≤), because the number can't be higher than 216, but it could be right at that number or less, so the equation is 8x + 12y ≤ 216. The answer is A.
Answer:
How many five-card hands dealt from a standard deck of 52 playing cards are all of the same suit? If a random hand is dealt, what is the probability that it will have this property?
Would the probability be:
(135)∗(41)(525)
