Answer:
aaaaasssdfghhjjkllllllqqqwwweerrrtyuiioppppZxcvbnmdffghjjklqqwertyukl;sdfghj
Step-by-step explanation:
Answer:
A
Pls mark brainliest
Answer:
![x_{1} = 3 + \sqrt {6}](https://tex.z-dn.net/?f=%20x_%7B1%7D%20%3D%203%20%2B%20%5Csqrt%20%7B6%7D%20)
![x_{2} = 3 - \sqrt {6}](https://tex.z-dn.net/?f=%20x_%7B2%7D%20%3D%203%20-%20%5Csqrt%20%7B6%7D%20)
Step-by-step explanation:
Given the quadratic equation;
x² - 6x + 3 = 0
To find the roots of the quadratic equation, we would use the quadratic formula;
Note: the standard form of a quadratic equation is ax² + bx + c = 0
a = 1, b = -6 and c = 3
The quadratic equation formula is;
Substituting into the formula, we have;
![x_{1} = \frac {6 + 2 \sqrt {6}}{2}](https://tex.z-dn.net/?f=%20x_%7B1%7D%20%3D%20%5Cfrac%20%7B6%20%2B%202%20%5Csqrt%20%7B6%7D%7D%7B2%7D%20)
![x_{1} = \frac {6}{2} + \frac {2 \sqrt {6}}{2}](https://tex.z-dn.net/?f=%20x_%7B1%7D%20%3D%20%5Cfrac%20%7B6%7D%7B2%7D%20%2B%20%5Cfrac%20%7B2%20%5Csqrt%20%7B6%7D%7D%7B2%7D%20)
![x_{1} = 3 + \sqrt {6}](https://tex.z-dn.net/?f=%20x_%7B1%7D%20%3D%203%20%2B%20%5Csqrt%20%7B6%7D%20)
Or
![x_{2} = \frac {6 - 2 \sqrt {6}}{2}](https://tex.z-dn.net/?f=%20x_%7B2%7D%20%3D%20%5Cfrac%20%7B6%20-%202%20%5Csqrt%20%7B6%7D%7D%7B2%7D%20)
![x_{2} = \frac {6}{2} - \frac {2 \sqrt {6}}{2}](https://tex.z-dn.net/?f=%20x_%7B2%7D%20%3D%20%5Cfrac%20%7B6%7D%7B2%7D%20-%20%5Cfrac%20%7B2%20%5Csqrt%20%7B6%7D%7D%7B2%7D%20)
![x_{2} = 3 - \sqrt {6}](https://tex.z-dn.net/?f=%20x_%7B2%7D%20%3D%203%20-%20%5Csqrt%20%7B6%7D%20)
Answer:
4/3
Step-by-step explanation:
tan is opposite/adjacent
tan A is 12/9
12/9 simplified is 4/3
Answer:
1,225
Step-by-step explanation:
you mutuply the sides