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Nezavi [6.7K]
3 years ago
5

Help please!!!!!!!!!

Mathematics
1 answer:
faltersainse [42]3 years ago
8 0
When the denominator = 0 and the numerator does not, you get a vertical asymptote.  That said a = - 1

If the exponents on the highest variable are the same in the horizontal asymptote is the division of coefficient on the top with the bottom. In plain English what that means is that if you make m = 1 then the coefficients are 2 and 1 (2 in the numerator and 1 in the denominator). If m is any other value greater than 1 there is not a horizontal asymptote.

C <<<====answer.
Third one down.






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Find the 20th term of the following sequence.
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Martha’s biweekly gross pay is $1,000. Her deductions make up 23% of her gross pay. How much is deducted from her pay for a full
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If √3 = 1.732, then √[(√3-1)/(√3+1)] is equal to​
adelina 88 [10]

Step-by-step explanation:

<h3><u>Given Question :-</u></h3>

\sf \:  \sqrt{3} = 1.732, \: then \:  \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} }

\red{\large\underline{\sf{Solution-}}}

Given expression is

\rm :\longmapsto\: \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} }

<em>On rationalizing the denominator, we get </em>

\rm \:  =  \:  \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1}  \times \dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  - 1} }

\rm \:  =  \:  \sqrt{\dfrac{ {( \sqrt{3}  - 1)}^{2} }{( \sqrt{3}  + 1)( \sqrt{3}  - 1)} }

<em>We know, </em>

\boxed{ \tt \: (x - y)(x + y) =  {x}^{2} -  {y}^{2} \: }

<em>So, using this, we get </em>

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{ {( \sqrt{3})}^{2}  -  {(1)}^{2} } }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{ 3 - 1} }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{2} }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{2} } \times \dfrac{ \sqrt{2} }{ \sqrt{2} }

\rm \:  =  \: \dfrac{(1.732 - 1) \sqrt{2} }{2}

\rm \:  =  \: \dfrac{0.732 \times \sqrt{2} }{2}

\rm \:  =  \: 0.366 \sqrt{2}

Hence,

\rm :\longmapsto\: \boxed{ \rm{ \: \:  \:   \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} } = 0.366 \sqrt{2} \:  \:  \: }}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>More Identities to know :- </h2>

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)² = (a - b)² + 4ab

(a - b)² = (a + b)² - 4ab

(a + b)² + (a - b)² = 2(a² + b²)

(a + b)³ = a³ + b³ + 3ab(a + b)

(a - b)³ = a³ - b³ - 3ab(a - b)

3 0
3 years ago
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