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3 years ago

How many of the group randomly selected are male/female

Mathematics

1 answer:

olchik [2.2K]3 years ago

6 0

50 percent of the group randomly selected that are male and female

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The rates of change, true or false

GenaCL600 [577]

Answer:

True, True, False

Step-by-step explanation:

1 is true because y values are increasing as x increases for both

2 is true because b's rate of change is 2 and a's rate of change is 0.25, so 2/0.25=8.

3 is false because a's y intercept is at 1

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2 years ago

Which one of the following statements is true of perpendicular lines?

miv72 [106K]

A. Thay intersect at one point.

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3 years ago

Which of these statements is true? A. The interior angles of both a regular and irregular pentagon have a sum of 540o. B. The in

Varvara68 [4.7K]

Answer:

Option A is the correct answer.

Step-by-step explanation:

The sum of interior angles of a polygon is given by (n-2) x 180°, where n is the number of sides.

The sum of interior angles will not affect irregularity of polygon, it is same for regular and irregular polygon.

For a pentagon n =5.

Sum of interior angles = (5-2) x 180 = 3 x 180 = 540°

Option A is the correct answer.

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3 years ago

Write the prime factorization for 168

11Alexandr11 [23.1K]

$168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7$

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3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago