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brilliants [131]
3 years ago
11

What is the value of |n|=5

Mathematics
2 answers:
nikdorinn [45]3 years ago
7 0

Answer:

n = 5 or -5

Step-by-step explanation:

the absolute value is the count away from 0 so n could be 5 which is 5 units from 0 or -5 which is also 5 units away from 0.

Ainat [17]3 years ago
7 0

Answer: n= -5, 5

Step-by-step explanation:

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What is a hundredths block shaded in fully and another hundredths block shaded in with 3 give you as fraction and decimal or mix
Leni [432]
A fraction and decimal because it equals 1 30/100 or 1 .03.
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Which of the points do not lie on X-axis P(0,3), Q(1,0), R(0, -1), S(-5, 0), T(1, 2) do not lie on X-axis
Anna71 [15]

Answer:

c) P, R, and T

Step-by-step explanation:

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3 years ago
Sin(x)^4+ cos(x)^4=1/2
posledela
I'll assume that what was meant was \sin ^4 x + \cos ^4 x = \dfrac{1}{2}.

The exponent in the funny place is just an abbreviation:   \sin ^4 x = (\sin x)^4.

I hope that's what you meant. Let me know if I'm wrong.

Let's start from the old saw

\cos^2 x + \sin ^2x = 1

Squaring both sides,

(\cos^2 x + \sin ^2x)^2 = 1^2

\cos^4 x + 2 \cos ^2 x \sin ^2x +\sin ^4x = 1

\cos^4 x + \sin ^4x = 1 - 2 \cos ^2 x \sin ^2x

So now the original question 

\sin ^4 x + \cos ^4 x = \dfrac{1}{2}

becomes
1 - 2 \cos ^2 x \sin ^2x = \dfrac{1}{2}

4 \cos ^2 x \sin ^2x = 1

Now we use the sine double angle formula

\sin 2x = 2 \sin x \cos x

We square it to see

\sin^2 2x = 4\sin^2 x \cos^2 x = 1

Taking the square root,

\sin 2x = \pm 1

Not sure how you want it; we'll do it in degrees. 

When we know the sine of an angle, there's usually two angles on the unit circle that have that sine.  They're supplementary angles which add to 180^\circ.  But when the sine is 1 or -1 like it is here, we're looking at 90^\circ and -90^\circ, which are essentially their own supplements, slightly less messy. 

That means we have two equations:

\sin 2x = 1 = \sin 90^\circ

2x = 90^\circ + 360^\circ k \quad integer k

x = 45^\circ + 180^\circ k

or 


\sin 2x = -1 = \sin -90^\circ

2x = -90^\circ+ 360^\circ k

x = - 45^\circ + 180^\circ k

We can combine those for a final answer,

x = \pm 45^\circ + 180^\circ k \quad integer k

Check.  Let's just check one, how about

x=-45^\circ + 180^\circ = 135^\circ

\sin(135)= 1/\sqrt{2}

\sin ^4(135)=(1/\sqrt{2})^4 = 1/4

\cos ^4(135)=(-1/\sqrt{2})^4 = 1/4

\sin ^4(135^\circ) +\cos ^4(135^\circ) = 1/2 \quad\checkmark


6 0
3 years ago
the two triangles shows the congruent ABC LMN. based on this information which of the following is a true statement ​
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Answer:

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Answer:

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Step-by-step explanation:

take the square root of both sides

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y=13

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