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2 years ago

What is the value of |n|=5

Mathematics

2 answers:

nikdorinn [45]2 years ago

7 0

Answer:

n = 5 or -5

Step-by-step explanation:

the absolute value is the count away from 0 so n could be 5 which is 5 units from 0 or -5 which is also 5 units away from 0.

Ainat [17]2 years ago

7 0

Answer: n= -5, 5

Step-by-step explanation:

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Simplify and solve for the unknown. Use order of operations as needed. Check your work.

antiseptic1488 [7]

Answer:

Step-by-step explanation:

Given: 5^3– 10^2 = X(8 – 2) + 2X – 3X

Solving the equation to find the value of x.

⇒ $5^{3} -10^{2} = x(8-2)+2x-3x$

Using the distributive property of multiplication, multiplying x with 8 and -2

⇒ $125-100= 8x-2x+2x-3x$

cancelling out -2x and 2x

⇒ $25= 8x-3x$

⇒ $25= 5x$

Multiplying both side by 5

⇒ x= $\frac{25}{5}$

∴ x= 5

Hence, the value of unknown is 5.

3 0

2 years ago

Which of the following is equal to the expression below? (160x243)^1/5

Kipish [7]

160 = 2 x 2 x 2 x 2 x 2 x 5 = 2^5 x 5
243 = 3 x 3 x 3 x 3 x 3 = 3^5
So
(160 * 243)^1/5
= 5th root of (160 * 243)
= 5th root of (2^5 * 5 * 3^5)
= 2 * 3 * (5th root of 5)
= 6 * (5th root of 5)
Answer is D. 6 * (5th root of 5)

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=3%5En%5E%2B%5E1%2B9%2F3%5En%5E-%5E1%2B1" id="TexFormula1" title="3^n^+^1+9/3^n^-^1+1" alt="3^n

abruzzese [7]

Answer:

Hello,

Step-by-step explanation:

$\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\$

4 0

2 years ago

Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation

Anestetic [448]

Answer:

27 hours

Step-by-step explanation:

Just do the reverse. 65-11 = 54. 54 / 2 = 27.

5 0

2 years ago

There are infinitely How many pairs of numbers of which the sum of their cube roots is zero give two of these pairs

ivanzaharov [21]

Answer:

Infinite pairs of numbers

1 and -1

8 and -8

Step-by-step explanation:

Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:

$\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y$

Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.

Examples: 1 and -1; 8 and -8; 27 and -27.

8 0

3 years ago