Ask question

Ask question

All categories

2 years ago

10

If I have 5 Orange Cats And 14 Black cats How many Cats Will there be left altogether and in colours if 2 Orange Cats get lost a

nd 6 Black cats get bought

1 answer:

eimsori [14]2 years ago

7 0

So, we will start by subtracting the orange cats

5-2=3 orange cats left

Then the black cats

14-6=8

Now we will add them back together:

8+3=11 Cats remaining

You might be interested in

Sandra has the following data:

Ludmilka [50]

The number "R" could be "A" and "D" because the range is 14 it cant be "B" or "C"

5 0

1 year ago

Read 2 more answers

it costs $12 to attend a golf clinic with a local pro. Buckets of balls for practice during the clinic costs $3 each. How many b

goldfiish [28.3K]

Answer: If you take out the price of the golf clinic with a local pro, you could buy 6 buckets.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

2 years ago

Can anyone help ? I need to answer it for my homework today

Rus_ich [418]

Robot 1- W = 20(3m) W= 60Nm
Robot 2- W= 30N (3m), W = 90Nm
Robot 3- W= 10N(2m), W= 20Nm
Robot 4- W= 30N(2m), W= 60Nm

Robot 2 did the most work, Robot 3 did the least amount of work and Robots, 1 and 4 did an equal amount of work

5 0

2 years ago

larisa [96]

Step-by-step explanation:

1/3,0,9

9,3,27

1/9,3,27

3 0

2 years ago