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3 years ago

8

Jack baked 38 biscuits. he can store them in boxes of 10 or as single biscuits. what are all of the different way Jack and store

d them biscuits?

1 answer:

ELEN [110]3 years ago

8 0

He can individually store all 38, or he can put 3 boxes of ten with 8 individuals, or he can 3 boxes of ten and one box that only contains eight.

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Sorry i didnt mean to post anything

Dmitry [639]

Hi you seem nice I like hot cocoa and I’m a littleAnd 1+1 is two and 3+3 is six and 9+9 is 18

4 0

2 years ago

Factor the expression.<br> 3x2 + 14x-5

Irina18 [472]

Answer:

(3x-1)(x+5)

Step-by-step explanation:

Find two numbers that when they multiply, you get the third term,

which is -5 in this problem. And when they add up, you get the second term,

which is 14 in this problem.

8 0

3 years ago

Which expression is equivalent to (3x-6)(4x+1)

vodka [1.7K]

Answer:

12x^2 -21x -6

Step-by-step explanation:

(3x-6)(4x+1)

FOIL

first 3x*4x= 12x^2

outer 3x*1 = 3x

inner -6*4x = -24x

last -6*1 = -6

Add them together

12x^2 +3x -24x -6

Combine like terms

12x^2 -21x -6

8 0

2 years ago

Drag each number to the box on the right so it matches the value of the expression on the left. Each number may be used once, mo

Ymorist [56]

Answer:

$-62024.48$

Step-by-step explanation:

Given

$[ 4 * ( 4 + 3 ) ] - 3 [ ( 7 - 5 ) \div 1 2 ] * 2 ( 5.4 + 3 ) * ( 6 - 2 ) [ 9 \div 3 + 6 ] * 3 ( 4 + 3.2 ) * [ ( 9 - 2 ) + 2.5]$

Required

Solve

The question is poorly formatted; the only way to answer this is to place the result of each step in brackets until brackets cannot be used.

So, we have

$[ 4 * ( 4 + 3 ) ] - 3 [ ( 7 - 5 ) \div 1 2 ] * 2 ( 5.4 + 3 ) * ( 6 - 2 ) [ 9 \div 3 + 6 ] * 3 ( 4 + 3.2 ) * [ ( 9 - 2 ) + 2.5 ]$

Solve the expressions in the inner brackets

$[ 4 * 7 ] - 3 [ 2 \div 1 2 ] * 2 ( 8.4 ) * ( 4 ) [ 9 \div 3 + 6 ] * 3 ( 7.2 ) * [ 7 + 2.5 ]$

Solve all divisions

$[ 4 * 7 ] - 3 * \frac{1}{6} * 2 ( 8.4 ) * ( 4 ) [ 3 + 6 ] * 3 ( 7.2 ) * [ 7 + 2.5 ]$

$[28] - 0.5 * (16.8) * (4) [9] * (21.6) * [9.5]$

$[28] - 0.5 * (16.8) * [36] * (21.6) * [9.5]$

Multiply through

$28- 62052.48$

$-62024.48$

3 0

2 years ago

Express the number 220 as the sum of four numbers that form a geometric progression such that the third term is greater than the

siniylev [52]

Answer:

Step-by-step explanation:

The first four terms of geometric series is:

$a,ar,ar^2,ar^3$

Since, we have given information that the third number is greater than 44 that means:

$ar^2=a+44$

Above equation can be rewritten as:

$a(r^2-1)=44$

Now, using:

$a^2-b^2=(a+b)(a-b)$

Here, a=r,b=1

$a(r+1)(r-1)=44$ (1)

The sum of first four terms is:

$a+ar+ar^2+ar^3=220$

$a(1+r+r^2+r^3)=220$

$a(1(1+r)+r^2(1+r))=220$

$a((1+r)(1+r^2))=220$ (2)

Divide equation (2) by (1) we get:

$\frac{r^2+1}{r-1}=\frac{220}{44}$

$r^2+1=5r-5$

$\Rightarrow r^2-5r+6=0$

$\Rightarrow r^2-3r-2r+6=0$

$\Rightarrow r(r-3)-2(r-3)=0$

$\Rightarrow (r-2)(r-3)=0$

$\Rightarrow r=2,3$

CASE1: When r=2 in $ar^2=a+44$

$a(4)=a+44$

$3a=44$

$a=\frac{44}{3}$

CASE2:When r=3 in $ar^2=a+44$

$a(3)^2=a+44$

$\Rightarrow 9a=a+44$

$\Rightarrow 8a=44$

$\Rightarrow a=\frac{44}{8}=\frac{11}{2}$

The series becomes:

From CASE1: $\frac{44}{3},\frac{44\cdot 2}{3},\frac{44\cdot 2^2}{3},\frac{44\cdot 2^3}{3}$

$\Rightarrow \frac{44}{3},\frac{88}{3},\frac{176}{3},\frac{352}{3}$

From CASE2: $\frac{11}{2},\frac{11\cdot 3}{2},\frac{11\cdot 3^2}{2},\frac{11\cdot 3^3}{2}$

$\Rightarrow \frac{11}{2},\frac{33}{2},\frac{99}{2},\frac{297}{2}$

6 0

3 years ago

Read 2 more answers