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3 years ago

13

Look at the table showing prices of different items at a store.

2 answers:

Natalija [7]3 years ago

7 0

notebooks and paperback

slega [8]3 years ago

3 0

Paperbacks and notebooks because their unit rates (UR) are $3.55 and $3.59, respectively, and both values are less than $3.75. The unit rates of puzzles and picture frames, $3.95 and $3.80, respectively, are greater than $3.75.

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Click on the length of the rectangle<br><br>

umka2103 [35]

Answer:

It's 2 1/4

Step-by-step explanation:

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Lauren deposited $3,000 into a savings account with an annual interest rate of 0.75%. She made no deposits or withdrawals for 3

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3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

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3 years ago

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Answer: HI ; ) Im ready......Okay whats the question?

Step-by-step explanation:

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What is the 6th row of Pascal's triangle?

Grace [21]

Answer:

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