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ZanzabumX [31]
3 years ago
11

Use the graph below to answer the following question:

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
2 should be your answer
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A broken calculator can double any number or permute its digits (but 0 cannot go up front). Can we start with number 1 and obtai
stira [4]

Answer: it's impossible to obtain 78

Step-by-step explanation: Since the calculator can double any number or permute its digits except 0 

starting with number 1 

1, 2, 4, 8, 16, 32, 64, 128

Therefore, it's impossible to obtain 78 by a series of these operations

8 0
2 years ago
Graph the line with slope 4 and y-intercept -7
antoniya [11.8K]

Start on -7 since it is the y intercept(b). 4/1 is the slope. So from seven you would go up 4 right 1.

7 0
3 years ago
Read 2 more answers
Mikki is taking her test and comes across the following question:
kicyunya [14]

Answer:

A. Normal distribution

Step-by-step explanation:

I just did it on usatestprep

6 0
3 years ago
2,10,18,26 find the 61st term
saw5 [17]

Answer:

482

Step-by-step explanation:

We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

a_{n} =a_{1} +(n-1)d

Where a_{1} is the first term, a_{n} is the nth term, and d is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 10-2, which is 8 , or the common difference. Since we have everything we need, it can be plugged into the equation:

a_{61} =2 + (61 - 1)*8\\a_{61} = 2 + 60*8\\a_{61} = 2 + 480\\a_{61} = 482

So, the 61st term is 482.

4 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
Read 2 more answers
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