Answer:
All numbers less than 2 or ![(-\infty, 1]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%201%5D)
or 
Step-by-step explanation:
Given that:
Number is added to itself is less than the number subtracted from 6.
To find:
All such numbers.
Solution:
Let the number be 
.
Here, an inequality will be made.
When solved, it might give more than one answers.
As per the question statement, let us write the inequality.
Number added to itself 
Number subtracted from six = 
As per question:
So, the answer is:
All numbers less than 2 or or .
Answer:
10 lines of symmetry...hope this helps:)
Answer:
x>-2
Step-by-step explanation:
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
1,000 is both a rational number and a whole number.
If my answer helped, please mark me as the brainliest!!
Thank You!!
