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X is the number
<span>The sum of two numbers is 11, so other number is : 11 - x
</span><span>The sum of their squares is 65
</span>
x^2 + (11 - x)^2 = 65
x^2 + 121 - 2(x)(11) + x^2 = 65
2x^2 - 22x + 121 = 65
2x^2 - 22x + 121 - 65 = 0
2x^2 - 22x + 56 = 0
2(x^2 - 11x + 28) = 0
2(x - 7)(x -4 ) = 0
x - 7 = 0
x = 7
x - 4 =0
x =4
answer: the numbers are 4 and 7
double check:
<span>sum of two numbers is 11:
4 + 7 = 11
</span><span>The sum of their squares is 65
</span><span>4^2 + 17^2 = 16 + 49 = 65
</span>
Because the coefficient of x^2 is -1, we know that a will be -1. Knowing that the coefficient of x is -4, we can calculate that p=2. Thus, we have -1(x+2)^2+q is our equation. This is equal to -x^2-4x-4+q. As the constant term must be 2, we can then see that q is 6.
As such, we have -1(x+2)^2+6=0 as our factorization.
To solve this equation, we can use the quadratic formula. Plugging in values, we have:
which is equal to: (when the fraction is simplified)
Answer: $37077.12
Step-by-step explanation:
Please see the attachment below