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Studentka2010 [4]
4 years ago
7

What is the value of the expression?

Mathematics
1 answer:
Vesnalui [34]4 years ago
4 0

1.583 3 is repeating

Hope this help you !

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Evaluate: 15+6-13-(-12)
rosijanka [135]

The answer is 20.

First you would multiple the negative with the negative 12, then you just add/subtract.

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3 years ago
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Rose borrows five dollars from her father to buy items at a gas station. Rose also borrows $11 my from her brother par a rose pa
Aneli [31]
Lets start this by seeing what Rose has done:
first she borrows $5, then she borrows another $11. she then pays back $3.50 of the $5 and $9.50 of the $11.
knowing this, we can use a number line to help solve this problem. first, we would make a mark at 5 on your number line, then go up the number line 11 more times until you reach 16. once youre at 16, you need to jump backwards down the number line 3 1/2 spots. this would leave you at 13 1/2, which would leave a dot halfway in between 13 and 14. now, you need to back 9 1/2 more spots so you can see how much she owes to her brother and father. if youre at 13 1/2 on your number line, and go back, or subtract, 9 1/2 spots you end up 4. this means that Rose owes $4 still. if you do not understand this process, i will include a picture below of my number line and you can follow along to the steps written above on the number line.
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Download pdf
3 0
4 years ago
How many months of the year have 28 days??
My name is Ann [436]
All 12 months have 28 days in it.
because every month has 28 days ( February) or more number of days like the other months(Jan, Mar..)
4 0
3 years ago
What is the sum of (5x - 10) and (-X + 8) ?
Darya [45]
4x-253 urge ytrv 57843 t58
7 0
3 years ago
Sqrt(2−7x) -sqrt(x 3) =3
Assoli18 [71]
(a+b)^2=a^2+2ab+b^2  \\ \\  \sqrt{2-7x} - \sqrt{x+3} =3 \\  (\sqrt{2-7x})^2  =(3 + \sqrt{x+3})^2\\2-7x=9+6\sqrt{x+3}+x+3 \\ 2-7x-9-x-3=6\sqrt{x+3} \\ (-8x-10)^2=(6\sqrt{x+3})^2 \\64x^2+160x+100=36(x+3) \\ 64x^2+160x+100=36x+108\\ 64x^2+160x-36x+100-108=0 \\ 64x^2+`124x-8=0 \\ 4( 16x^{2} +31x-2)=0 \\
16x^{2} +31x-2=0 \\(x-2)(16x-1)=0 \\ x+2=0 \\ x=-2 \\ 16x-1=0 \\ x= \frac{1}{16}

\sqrt{2-7  \cdot\frac{1}{16} } - \sqrt{\frac{1}{16} +3}  \neq 3 \\ x=-2


6 0
3 years ago
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