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Alex17521 [72]
3 years ago
13

Homologous pairs separate in meiosis , and sister chromatids separate in meiosis .

Biology
1 answer:
puteri [66]3 years ago
6 0

Answer:

Homologous pairs separate in first round of meiosis or meiosis 1

However,

sister chromatids separate in second round of meiosis or meiosis 2.

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A brown bird was crossed with a white one and all of the offspring were tan. Complete a Punnett Square analysis for this pair to
Alex73 [517]

Answer:

here.

Explanation:

The genes coding for colour show codominance. Both the brown and white pigment are equally expressed in the phenotype to give the tan colour.

Considering that the allele for brown pigment is CB and that for white pigment is CW, the genotype for the brown bird is CB CB and that for the white bird is CW CW.

Crossing CB CB × CW CW,

100% CB CW - tan-coloured birds

3 0
3 years ago
What determines the end of the Hadean Eon is
marusya05 [52]

Answer:

A. Early signs of life on earth

Explanation:

The Hadean, before the Archean, is the first geologic eon of Earth. It began with the formation of the Earth about 4600 million years ago and ended 4,000 million years ago. The planet had just formed and was still very hot due to high volcanism, a partially molten surface. Some geologists labels the period before the earliest-known rocks on Earth. At the end of it much cooler surface temperature and the formation of solid rock enabled to flaurish the life.

3 0
3 years ago
In garden peas a pure line that is tall with purple flowers is crossed to another pure line that is short with white flowers. Th
defon

Answer:

See the explanation

Explanation:

Answer 1.

As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.  

Let S for short s for tall and W for white and w for purple allele.

So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,

................ Sw .................... sw

Sw ........ SSww ............. Ssww

sw ........ Ssww .............. ssww (tall and purple)

So from this 1/4 will be tall and purple while 3/4 will be short and purple.

In second case SSww only short purple progeny will appear.

Answer 2.

2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.

2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.

2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.

2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.

Hope this helps!

4 0
3 years ago
Ira is working in a lab with unknown solution.when he inserts the electrical conductivity tester in the unknown,the bulb begins
Mamont248 [21]
Electrical conductivity tester.

If the bulb begins to glow brightly when the plug is submerged in the unknown solution then the solution has high conductivity. 

The bright glow of the bulb resulting from the experiment indicates that the current flows easily through the unknown liquid.
7 0
3 years ago
All of the following statements are true about heritability EXCEPT: Group of answer choices it is the genetic variance for a tra
Lerok [7]

Answer:

I am a in

Explanation:

I apologize I don't know the answer

3 0
2 years ago
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