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Verizon [17]
3 years ago
9

The test scores of 32 students are listed below. Construct a boxplot for the data set and include the values of the 5-number sum

mary. 32 37 41 44 46 48 53 55 57 57 59 63 65 66 68 69 70 71 74 74 75 77 78 79 81 82 83 86 89 92 95 99

Mathematics
1 answer:
zhenek [66]3 years ago
7 0

Answer:

Boxplot is constructed using quartiles and 5 No. summary means including minimum value of data, 1st quartile, 2nd quartile, 3rd quartile and maximum value of data.

As data already in increasing order, we find quartiles using the following formula,

value\:of\:K_{th}\:Quartile\:,\, Q_k=\:value\:of\:(\frac{k\times{(n+1)}}{4})\,\:th\,observation

where n = No. of Observations.

∴, 1st Quartile,

Q_1 = \frac{1\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=8.25\,th\:observation\\\: \:\:= 8th\,+0.25(9th-8th)\\\:\:\:= 55 + 0.25(57-55)\\\:\:\:= 55.5

2nd Quartile,

Q_2 = \frac{2\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=16.5\,th\:observation\\\: \:\:= 16th\,+0.5(17th-16th)\\\:\:\:= 69 + 0.5(70-69)\\\:\:\:= 69.5

3rd Quartile,

Q_3 = \frac{3\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=24.75\,th\:observation\\\: \:\:= 24th\,+0.75(25th-24th)\\\:\:\:= 79 + 0.75(81-79)\\\:\:\:= 80.5

Minimum value of data = 32 & Maximum value of data = 99

So, Values of 5 no. that are to ne include in Boxplot are 32, 55.5, 69.5, 80.5, 99.

BoxPlot is attached with this ans.

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Answer:

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Step-by-step explanation:

so we are given the diameter which is 42m **the diameter is the straight line that passes through the middle of the circle**

but in order to find the circumference we need to find the radius **the radius is always half (1/2,0.5) of the diameter**

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and in your case, it seems we must round to the tenths place so the nine then "becomes a ten" and you're left with 132

good luck :)

i hope this helps

have a good one !!

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