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3 years ago

What is the Prime Factorization of 36

Mathematics

2 answers:

Schach [20]3 years ago

4 0

: The prime factorization of 36 is 4 ? 3^2 ,False . 
Prime factorization for 36 = 2*2*3*3

nasty-shy [4]3 years ago

3 0

First you must know what the primes are, which are numbers that have only 1 and themselves as factors...(look em up and remember as many as you can as they come up again and again in mathematics :P)

Then you factor your number with these primes from least to greatest...

36=2*2*3*3 or you could say:

36=2^2(3^2)

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Evaluate the expression if r = 12 and t = -6. (t-r)/3

Lynna [10]

Answer:

-6

Step-by-step explanation:

$\frac{(t-r)}{3}$

input the numbers

$\frac{(-6-12)}{3}$

do the problem in the parentheses first

-6-12 = -18

now it becomes

$-\frac{18}{3}$

simplify and you'll get

-6

this is because -18 ÷ 3 =

-6

4 0

3 years ago

Read 2 more answers

URGENT!!!! What is the distance from (−2, 4) to (0, −6)? Round your answer to the nearest hundredth. 9.23 units 10.20 units 10.9

serg [7]

The distance between two points knowing theirs coordinates:

AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(-2,4) & B(0,-6) Given
A(x₁,y₁) & B(y₂,y₁)

AB =√[(0-(-2))²+(-6-4)²] =√(104) = 10.198 ≈ 10.2

8 0

3 years ago

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What is negative times x plus 7

ValentinkaMS [17]

-.x+7
-x+7=0
-x=-7
x=7...

Not too sure because of the way you wrote the question but this is the interpretation i gave it.

3 0

3 years ago

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Which steps show how to use the distributive property to evaluate 9.32?

MAVERICK [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

What is the following product? (4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago