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Anestetic [448]
4 years ago
7

Find the value of W if A=LW, A=16m^2 L=8m W=?

Mathematics
2 answers:
Natasha2012 [34]4 years ago
8 0
So if A=LW
and A=16m^2
and L=8m
A=LW
16m^2=8m(W)
divide both sides by 8m
2m=W

or you could convert the equation A=LW to A/L=W to solve for W
so A/L=W  or (16m^2)/8m=W
cancel out one 'm'  (16m)/8=W
simplify the fraction 2m/1=W
2m=W
romanna [79]4 years ago
6 0
A=LW \\A=16m^2 \\\\ 16m^2=8m*W \\\\ W=16m^2:8m \\\\ \boxed{W=2m}
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Find all positive integer values of c that make x^2+6x+c factorable
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It's factorable when c  ∈ {5,8,9}
6 0
4 years ago
<img src="https://tex.z-dn.net/?f=4%284x-4%29%2Bx%2B4%3D-46" id="TexFormula1" title="4(4x-4)+x+4=-46" alt="4(4x-4)+x+4=-46" alig
muminat

Answer:

x=-2

Step-by-step explanation:

4(4x-4)+x+4=-46\\16x-16+x+4=-46\\17x-16+4=-46\\17x-12=-46\\17x=-34\\x=-2

8 0
2 years ago
Read 2 more answers
Calculate the value of the expression (Explain in words)<br><br> -30-(-20)
oee [108]

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-10

Step-by-step explanation:

when you subract a negative the minus signs negate each other

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST THANK YOU
Alina [70]

Answer:

\huge\boxed{\sf 46}

Step-by-step explanation:

<u>Formula for area of rectangle:</u>

= length × width

<u>Area of the smaller rectangle:</u>

length = 7

width = 6

= 7 × 6

= 42

<u>Area of the larger rectangle:</u>

length = 7 + 4 = 11

width = 6 + 2 = 8

= 11 × 8

= 88

<u>Area of the shaded region:</u>

= Area of the larger rectangle - Area of the smaller rectangle

= 88 - 42

= 46

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

5 0
3 years ago
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