Solution for x^2+5x=150 equation:
<span>Simplifying
x2 + 5x = 150
Reorder the terms:
5x + x2 = 150
Solving
5x + x2 = 150
Solving for variable 'x'.
Reorder the terms:
-150 + 5x + x2 = 150 + -150
Combine like terms: 150 + -150 = 0
-150 + 5x + x2 = 0
Factor a trinomial.
(-15 + -1x)(10 + -1x) = 0
Subproblem 1Set the factor '(-15 + -1x)' equal to zero and attempt to solve:
Simplifying
-15 + -1x = 0
Solving
-15 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '15' to each side of the equation.
-15 + 15 + -1x = 0 + 15
Combine like terms: -15 + 15 = 0
0 + -1x = 0 + 15
-1x = 0 + 15
Combine like terms: 0 + 15 = 15
-1x = 15
Divide each side by '-1'.
x = -15
Simplifying
x = -15
Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve:
Simplifying
10 + -1x = 0
Solving
10 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-10' to each side of the equation.
10 + -10 + -1x = 0 + -10
Combine like terms: 10 + -10 = 0
0 + -1x = 0 + -10
-1x = 0 + -10
Combine like terms: 0 + -10 = -10
-1x = -10
Divide each side by '-1'.
x = 10
Simplifying
x = 10Solutionx = {-15, 10}</span>
The last one will give the incorrect slope
Answer:
The juice left at the end of the day is 1.085 liters.
Step-by-step explanation:
Juice at the beginning of the day: 3.875 liters
Juice drink by Mario during the day: 2.79 liters
Juice left at the end of the day = Juice at the beginning of the day - Juice drink by Mario during the day
= 3.875 - 2.79
= 1.085 liters
Answer:
Quadrant I: (1,1), (4,3)
Quadrant II: (-2, 3), (-1, 1)
Step-by-step explanation:
Quadrant I points have positive x and y values. Quandrant II points have negative x values and positive y values.
