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NNADVOKAT [17]
4 years ago
11

I NEED HELP PLEASE I GIVE 5 STARS !

Mathematics
2 answers:
uranmaximum [27]4 years ago
8 0

Answer:

C. 2\sqrt{29}

Step-by-step explanation:

Square root of 116 is 10.7703296

Square root of 29 is 5.38516481, but as it is multiplied by 2, it becomes 10.7703296

vagabundo [1.1K]4 years ago
7 0

Answer:

C

Step-by-step explanation:

The square root of 116 is about ten. Two times the square root of 29 also equals about ten. A equals about 13. B equals about 9. And 13 equals 13 so only C can be correct.

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Jason paid $24 for a 30 pound bag of dog food. What was the cost per pound of the dog food?
katen-ka-za [31]

Answer:

$0.80 per pound

Step-by-step explanation:

I hope this helps <3

5 0
3 years ago
?????????? Help me ???
kupik [55]
(4x - 6y^3)^2 = (4x - 6y^3)(4x - 6y^3) = 16x^2 - 24xy^3 - 24xy^3 + 36y^6
= 16x^2 - 48xy^3 + 36y^6
7 0
4 years ago
What is the decibel level of a dog barking with intensity 10−5 watts per square inch? Use a logarithmic model to solve.
Vsevolod [243]

Answer:

The sound intensity is about 101.9 dB

Step-by-step explanation:

Sound intensity is the amount of sound energy per unit area.

The intensity of the dog bark is 10⁻⁵ W/in². The intensity of sound in decibels is given by:

\beta=10\ dB*log(\frac{I}{I_o} )\\\\Where\ I=Sound\ intensity\ in \ W/m^2, I_o=reference\ sound\ intensity=10^{-12}\ W/m^2\, \beta= sound\ intensity\ in\ dB

I = 10⁻⁵ W/in² = 0.0155 W/m²

Therefore:

\beta=10\ dB*log(\frac{I}{I_o} )\\\\\beta=10\ dB*log(\frac{0.0155}{10^{-12}} )\\\\\beta=101.9\ dB

The sound intensity is about 101.9 dB

5 0
3 years ago
Plz help I will mark you brainliest, also give an explanation if you can so I understand
Ulleksa [173]

Answer:

D

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{27}^{2}  +  {36}^{2}  = 2025  \\  {45}^{2}  = 2025

8 0
3 years ago
Read 2 more answers
4 yd<br> 4 yd<br> 20 yd<br> 24 yd<br> 20 yd<br> 24 yd<br> What is the perimeter?
Mice21 [21]

Answer:

96

Step-by-step explanation:

24+20+24+20+4+4=96

7 0
4 years ago
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