The factor "x" is the number 6
y = 4x + 1
for x = 0 → y = 4(0) + 1 = 1 → (0, 1)
for x = -1 → y = 4(-1) + 1 = -3 → (-1, -3)
Look at the picture.
Answer: (-3, 15)
Answer:
(a)The position of the particle after a time t is
(b)The position of the particle after a time t is
Step-by-step explanation:
We know that, the first order derivative of the position of an object is the velocity of the object.
(a)
Given that, the velocity of a particle moving in straight line is
Integrating both sides
[ c is an arbitrary]
The position of the particle after a time t is
(b)
Given that S= 3 at time t=0
The position of the particle after a time t is
We have that
<span>focus (-5, 3) and vertex (-5, 6)
</span>As the vertex <span>(−5,6)</span><span> and focus </span><span>(−5,3)</span><span> share same abscissa </span><span>−5</span><span>, parabola has axis of symmetry as </span><span>x=−5
</span>Hence, equation of parabola is of the type <span><span>(y−k)</span>=a<span>(x−h)</span></span>²<span>,
where </span><span>(h,k)</span><span> is vertex
</span>Its focus then is <span>(h,k+<span>1/(<span>4a)</span></span>)
(h,k)=(-5,6)
</span>(h,k+1/(4a))=(-5,3)
(y−k)=a(x−h)²-----> (y−6)=a(x+5)²
k+1/(4a)=3------> 6+1/(4a)=3-----> 1/(4a)=-3-----> a=-1/12
(y−6)=a(x+5)²------> (y−6)=(-1/12)*(x+5)²
the answer is(y−6)=(-1/12)*(x+5)²