Answer:
approximately 0.2 days
Step-by-step explanation:
Flow is defined as:
Q = V/t
where Q is flow, V is volume, and t is time
Let's call Vr to the volume of the reservoir, then for the first channel:
Q1 = Vr/t1
Replacing with t1 = 1/3 of day:
Q1 = Vr/(1/3) = 3*Vr
Similarly, or the other channels:
Q2 = Vr/1 = Vr
Q3 = Vr/(2 1/2) = 2/5*Vr
Q4 = Vr/3
Q5 = Vr/5
When all channels are open, the time needed to fill the reservoir is:
Vr = t*(Q1 + Q2 + Q3+ Q4 + Q5)
Replacing with the previous equivalences:
Vr = t*(3*Vr + Vr + 2/5*Vr+ Vr/3 + Vr/5)
Vr = t*4.93*Vr
1/4.93 = t
0.2 = t
To solve this, you need to plug in the numbers for <em>h</em>.
-4(-12) ≥ 8 48 ≥ 8 yes
-4(-7) ≥ 8 28 ≥ 8 yes
-4(-5) ≥ 8 20 ≥ 8 yes
-4(-3) ≥ 8 12 ≥ 8 yes
-4(-2) ≥ 8 8 ≥ 8 yes
-4(-1) ≥ 8 4 ≥ 8 no
-4(1) ≥ 8 -4 ≥ 8 no
-4(3) ≥ 8 -12 ≥ 8 no
-4(8) ≥ 8 -32 ≥ 8 no
Hope this helped!
Answer:
The distance when x = 6km is D = 498 KM
Step-by-step explanation:
Here, given the formula for the distance, we want to find the distance D given the value of x to be 6km
What we do simply here is to substitute the value 6km as x in the equation
The equation is
D = 4x^3 - 10x^2 -6
Substituting x = 6, we have
D = 4(6^3) -10(6^2) -6
D = 864-360-6
D = 498 km
<span>9x+2y=14 and 7x+2y=2
</span>⇒ x= 6
<span> y= -20</span>
