Complete the table below to find solutions to the linear equation −4x+4y=16.

Mathematics

1 answer:

Rama09 [41]3 years ago

7 0

Step-by-step explanation:

if x=4, then -4x4+4y=16

so, -16+4y=16

so, 4y=16+16=32

so, y=32/4

so, y=8

and x=4

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Select two polynomials that have a sum of 16n^3+13n^2+7n-10 A. 8n^3 - 5n +11n^2 - 5 B. 7n^2 + 8n - n^3 + 2 C. 15n^2 - 10n + 3n^3

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

We have the polynomial

$16n^3+13n^2+7n-10$ ( 1 )

To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

$8n_{3}-5n+11n^{2}-5\\7n^2 + 8n - n^3 + 2\\15n^2 - 10n + 3n^3 - 4\\2n^2 + 12n - 5 + 8n^3$

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have

$8n^3 +11n^2 - 5n - 5\\ 8n^3+2n^2 + 12n - 5\\$

and if we sum we obtain

$16n^3+13n^2+7n-10$

that is what we was looking for

I hope this is useful for you

regards

7 0

2 years ago

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allochka39001 [22]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

What is HB? Triangle Mid-segment Theorem

Scorpion4ik [409]

Answer:

HB = 13

Step-by-step explanation:

In triangle GHJ, points A, B, C are mid points of the sides GH, HJ, GJ respectively.

Therefore by Mid-segment Theorem.

$AC = \frac{1}{2} HJ \\ \\ 3y - 5 = \frac{1}{2} (4y + 2) \\ \\ 3y - 5 = \frac{1}{2} \times 2 (2y + 1) \\ \\ 3y - 5 = 2y + 1\\ \\ 3y - 2y = 5 + 1 \\ \\ y = 6 \\ \\ HJ = 4y + 2 \\ \\ HJ = 4 \times 6 + 2 \\ \\ HJ = 24 + 2 \\ \\ HJ = 26 \\ \\ HB= \frac{1}{2} HJ \\ \\ HB= \frac{1}{2} \times 26 \\ \\ \huge \red{ \boxed{ HB= 13}}$