Find the area bounded by the curves x = 2y2 and x = 1 - y. Your work must include an integral in one variable.

Mathematics

1 answer:

Sedbober [7]2 years ago

4 0

Answer:

Hello,

in order to simplify, i have taken the inverses functions

Step-by-step explanation:

$\int\limits^\frac{1}{2} _{-1} {(-2x^2-x+1)} \, dx \\\\=[\frac{-2x^3}{3} -\frac{x^2}{2} +x]^\frac{1}{2} _{-1}\\\\\\=\dfrac{-2-3+12}{24} -\dfrac{-5}{6} \\\\\boxed{=\dfrac{9}{8} =1.25}\\$

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In the equation 3/4y+1/2=3 1/4, the fractional coefficient is what

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Step-by-step explanation:

Given equation: $\frac{3}{4}y + \frac{1}{2} = 3 \frac{1}{4}$

In the given equation, $\frac{3}{4}$ is a coefficient and y is the variable.

coefficient is a constant number or quantity multiplied to a variable in an algebric expression. Like in the above equation $\frac{3}{4}$ is a coefficient and y is the variable. We use term variable for y as its value may vary or change. If variable does not have any coefficient in any expression then in that case, we consider 1 as coefficient, for example: $x+4$ , here variable have 1 as coefficient.