Answer:

Find the midsegment of the triangle which is parallel to CA.

Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

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Distribution is multiplying. So
6(12)-6(5)
72-30
42
Answer:
Step-by-step explanation:
2.7*4=10.80
27*0.4=10.80 we multiplied 27 by 10 but divide 4 by 10
0.27*40=10.80
Answer:

Step-by-step explanation:
Let the time flown by the flying carpet be
. Then, we have that
.
We multiply both sides of the equation by
to get
.
We subtract
from both sides to get
.
We divide both sides of the equation by
.
We know that the speed of the flying carpet in still wind is the average of the rates of the speed of the flying carpet with the wind and against the wind.
The speed with wind is
mph.
The speed against wind is
mph.
The speed in still wind is
.
Therefore, the answer is
and we're done!
Answer: H
Step-by-step explanation:
Supplementary angles just mean they add up to 180 degrees. 180 degrees means that when the two angles are put together one of each of their sides will form a straight line.