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Shkiper50 [21]
3 years ago
5

Two integers have a product of,n, p, -24. what is the largest possible sum of n and p

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

n x p= -24

-2 x 12 is the largest possible numbers to put to get the answer of -24.

Reasoning: Trail and error is how i found the answer, using different combos of numbers to get the number.

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What te answer is to the question I do not know
pishuonlain [190]
Hello,

10 is not a digit!
Let' a ,b ,c the 3 digits
Numbers are
10a+b
10a+c
10b+c
10b+a
10c+a
10c+b
sum = 22a+22b+22c=22(a+b+c)

sum /(a+b+c)=22



4 0
3 years ago
The number of stops a bus makes on a certain day is represented by the variable s. Which set of numbers best describes the value
Alekssandra [29.7K]
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8 0
3 years ago
I have a homework about subtracting Integers and i don't get what -9 - 5, 31 - 48, ang -6 - 7 is
Alexxandr [17]
Well remember this:
When the signs are the same it is positive
When the signs are different make it negative

When you are subtracting a negative and positive, it is going to be like adding
for example:
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5 0
3 years ago
X^2+1/2x+____=2 + ____
natali 33 [55]

Answer:  x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}

Step-by-step explanation:

Given the following Quadratic equation:

x^2+\frac{1}{2}x=2 +

You can change its formed by Completing the square.

In order to do Complete the square, you can follow these steps:

1. You can identify that:

b=\frac{1}{2}

2. Then, you can find (\frac{b}{2})^2. This is:

(\frac{\frac{1}{2}}{2})^2=(\frac{1}{4})^2=\frac{1}{16}

3. Now you must add \frac{1}{16} to both sides of the Quadratic equation in order to keep the balance. Then:

x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}

4. Finally, simplifying by actoring and adding the like terms, you get:

(x+\frac{1}{4})^2=\frac{9}{4}

3 0
3 years ago
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