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2 years ago

What is the gradient of the graph shown? Give your answer in its simplest form.

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

4 0

Answer:

-2

Step-by-step explanation:

I think this was the question you were talking about.

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Gary deposits $1,500 into each of two savings accounts. Account I earns 5% annual simple interest. Account II earns 5% interest

hodyreva [135]

Answer:

$3623.26

Step-by-step explanation:

Given

Each deposit = $1500
Interest rate= 5%
Time = 4 years
Compound number = annual

Simple interest account

B = 1500*(1 + 4*0.05) = 1500*1.2 = $1800

Compound interest account

B = 1500*(1 + 0.05)^4 = $1823.26

Total balance

$1800 + $1823.26 = $3623.26

7 0

3 years ago

Find the compound Interest for Rs.18,800 ,calculated for 2 years at 13% rate of Interest compounded annually

Vinvika [58]

For compound interest, the formula is given below:

Amount = $P(1+\frac{r}{100} )^{n}$

Here, P = 18,800

n = 2

r = 13/100

So, Amount = $18,800(1+\frac{13}{100} )^{2}$

$18,800(1.13)^{2}$

= 18,800 × 1.2769

= 24005.72

Compound Interest = Amount - Principal

Compound Interest = 24005.72 - 18800

= 5205.72

Hence, the compound interest for Rs.18,800, calculated for 2 years at 13% rate of interest compounded annually is Rs.5205.72.

4 0

3 years ago

Solve each system using substitution. Check your answer 2x+2y=38 y=x+3

Mrac [35]

Your answer would be X=8 and Y=11.

4 0

3 years ago

Some pls help me with number 6

Katyanochek1 [597]

Answer:

m∠CBD = m∠CDB ⇒ proved

Step-by-step explanation:

Let us solve the question

∵ AB ⊥ BD ⇒ given

→ That means m∠ABD = 90°

∴ m∠ABD = 90° ⇒ proved

∵ ED ⊥ BD ⇒ given

→ That means m∠EDB = 90°

∴ m∠EDB = 90° ⇒ proved

∵ ∠ABD and ∠EDB have the same measure 90°

∴ m∠ABD = m∠EDB ⇒ proved

∵ m∠ABD = m∠ABC + m∠CBD

∵ m∠EDB = m∠EDC + m∠CDB

→ Equate the two right sides

∴ m∠ABC + m∠CBD = m∠EDC + m∠CDB

∵ m∠ABC = m∠EDC ⇒ given

→ That means 1 angle on the left side = 1 angle on the right side, then

the other two angles must be equal in measures

∴ m∠CBD = m∠CDB ⇒ proved

5 0

3 years ago

Someone please help me with this one quick

astraxan [27]

The length of AC is 16 km.

Solution:

Given data:

AB = c = 14 km, ∠A = 30° and ∠B = 89°

AC = b = ?

Let us first find angle C:

Sum of all angles in a triangle = 180°

m∠A+ m∠B + m∠C = 180°

30° + 89° + m∠C = 180°

119° + m∠C = 180°

Subtract 119° from both sides, we get

m∠C = 61°

To find the length of AC:

Using sine formula:

$$\frac{b}{\sin B } =\frac{c}{\sin C}$

Substitute the given values in the formula.

$$\frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ }$

Multiply by sin 89° on both sides.

$$\sin 89^\circ \times \frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ } \times \sin 89^\circ$

$$b=\frac{14}{0.8746 } \times0.9998$

$b=16$

The length of AC is 16 km.

4 0

3 years ago