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Furkat [3]
3 years ago
5

What is the value of n? 52+23+n=16

Mathematics
2 answers:
statuscvo [17]3 years ago
6 0
<span><span><span>52+23</span>+n</span>=16

</span>Step 1: Simplify both sides of the equation.

<span><span><span>52+23</span>+n</span>=16

</span><span>Simplify: (Show steps)

</span><span><span>n+75</span>=16

</span>Step 2: Subtract 75 from both sides.

<span><span><span>n+75</span>−75</span>=<span>16−75</span></span><span>n=<span>−59

</span></span>Answer:<span>n=<span>−<span>59

hope this helps you!</span></span></span>
pshichka [43]3 years ago
3 0
In order to find "n", you need to isolate it. So you would subtract 52 from both sides. You have 23+n=-36. Now, you subtract 23 from both sides. You have n=-59. Do you need any more clarification?
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Given f(x) = x ^ 2 - 6x + 8 and g(x) = x + 2 solve f(x) = g(x) . Use the tables below to help you, but please explain how you ca
Travka [436]

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = x² - 6x + 8 and g(x) = x + 2

To solve f(x) = g(x), equate the right sides, that is

x² - 6x + 8 = x + 2 ← subtract x + 2 from both sides

x² - 7x + 6 = 0 ← in standard form

(x - 1)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 6 = 0 ⇒ x = 6

These solutions can be verified from the tables, that is

f(x) = g(x) = 3 ← when x = 1

f(x) = g(x) = 8 ← when x = 6

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3 years ago
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2 years ago
If f ( x ) f(x) is an exponential function where f ( − 3.5 ) = 25 f(−3.5)=25 and f ( 6 ) = 33 f(6)=33, then find the value of f
gavmur [86]

Given:

f(x) is an exponential function.

f(-3.5)=25, f(6)=33

To find:

The value of f(6.5).

Solution:

Let the exponential function is

f(x)=ab^x         ...(i)

Where, a is the initial value and b is the growth factor.

We have, f(-3.5)=25. So, put x=-3.5 and f(x)=25 in (i).

25=ab^{-3.5}         ...(ii)

We have, f(6)=33. So, put x=6 and f(x)=33 in (i).

33=ab^{6}         ...(iii)

On dividing (iii) by (ii), we get

\dfrac{33}{25}=\dfrac{ab^{6}}{ab^{-3.5}}

1.32=b^{9.5}

(1.32)^{\frac{1}{9.5}}=b

1.0296556=b

b\approx 1.03

Putting b=1.03 in (iii), we get

33=a(1.03)^{6}

33=a(1.194)

\dfrac{33}{1.194}=a

a\approx 27.63

Putting a=27.63 and b=1.03 in (i), we get

f(x)=27.63(1.03)^x

Therefore, the required exponential function is f(x)=27.63(1.03)^x.

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Answer:

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Step-by-step explanation:

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