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valkas [14]
3 years ago
14

Use x=3 to identify the value of each expression.

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Exponents if those are the answer it bc the second number is an exponent

3^3= 27

4^3=64

3^4=81

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Solve the inequality 2x>30+5/4x
insens350 [35]

Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
LMNP is rotated 180 degrees clockwise around the origin. What are the coordinates of L?
Alona [7]

\huge\boxed{L^\prime(0, -1)}

To rotate a point around the origin by 180 degrees, multiply both parts of the coordinate point by -1. (This means you go from (x, y) to (-x, -y).)

L(0, 1)

L^\prime(0*(-1), 1*(-1))\\\boxed{L^\prime(0, -1)}

4 0
2 years ago
Anyone Know This Answer ?
OverLord2011 [107]
I hope this helps you



M^2+R^2=W^2



M^2+16=25



M^2=9
7 0
3 years ago
Read 2 more answers
F(x) has domain , and range
marta [7]
Domain: {-4, -2, 0, 2, 4}
range: {-2, -1, 0, 1, 2}
7 0
2 years ago
A soccer league has 200 players. Of those players 50% are boys. How many boys are in the soccer league
Lelechka [254]
What's 200 minus 50 that's your answer simple
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