Answer:
We have two 6-sided dice.
Each one of them has 6 possible outcomes.
The total number of outcomes for the pair, will be equal to the product between the numbers of outcomes for each one of them
Then the total number of outcomes is:
C = 6*6 = 36.
The number of outcomes where the sum of the dice are 7 are:
1 and 6
6 and 1
2 and 5
5 and 2
3 and 4
4 and 3
So we have 6 outcomes where the sum of both numbers is equal to 7.
The probability of rolling a pair such that the sum is equal to 7, is equal to the quotient between the number of outcomes that meet this condition (6) and the total number of outcomes (36)
The probability is:
P = 6/36 = 1/6
Now let's do the same for 11.
The outcomes where the sum is 11 are:
5 and 6
6 and 5
So we have two outcomes.
In this case, the probability will be:
P = 2/36 = 1/18
A squared plus b squared = c squared will help
The answer is 2a-4b. Hope this helps!
Answer:
Step-by-step explanation:
Um, where the triangle? If the no triangle how are we gonna answer your question?
( I'm not trying to be mean )
Answer:
a) QT = 8
b) QN = 24
c) QP = 23
d) MP = 46
e) RT = 6
f) TP = 12
Step-by-step explanation:
Find the diagram attached
If T is the centroid of<MNP, then the following are true;
TN = 2QT
Given TN = 16
16 = 2QT
QT = 16/2
QT = 8
QN = QT + TN
QN = 8 + 16
QN = 24
MQ + QP = MP and MQ = QP
If MQ = 23
QP = 23
Recall that MP = MQ + QP
MP = MQ + MQ
MP = 2MQ
MP = 2(23)
MP = 46
Similarly, TP = 2RT
RT = TP/2
Also RP = RT + TP
RP = RT + 2 RT
RP = 3RT
18 = 3RT
RT = 18/3
RT = 6
Recall that TP = 2RT
TP = 2(6)
TP = 12
