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zaharov [31]
3 years ago
6

Laura bought a pair of shoes for 20$. The shoes were on sale for 15% off, and she also used a coupon for an extra 20% off. Befor

e sales tax was applied, how much did Laura pay for the shoes?
Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

$13.60 before sales tax

Step-by-step explanation:

$20 x .85 (aka 15% off) = $17

then

$17 x .80 (aka 20% off) = $13.60

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Gnoma [55]
Answer:


I think is (B)
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Hi,so I've tried solving this problem for a while and I just don't get it,if you could give me some ideas I would appreciate it.
ziro4ka [17]

Answer:

187 cm²

Step-by-step explanation:

The bottom rectangle area is easy, it is 15*9 = 135 cm².

To find the area of the triangle, you only need the base width and its height (you don't need the hypotenuse). You can then use the formula: area triangle is base times half height.

The base width is 15-7 = 8 cm

The height is 22-9 = 13 cm

So the area of the triangle is 13*8/2 = 52 cm²

Together with the 135 of the rectangle that sums to 52+135 = 187 cm².

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3 years ago
Evaluate h-²g for h = 4 and g = 32.<br> 2<br> 1/2<br> 8
Hunter-Best [27]

Step-by-step explanation:

h2 - g

Putting values

(4)2 - 32

8 - 32

= - 24

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creativ13 [48]

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If each bottle costs 3 dollars, then the cost of b bottles would be 3b.

5 0
3 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
3 years ago
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