Answer:
=−7x2+19x+
41/3
Step-by-step explanation:
V=(4/3)pir^3
find smaller
V=(4/3)pi8^3
V=(4/3)pi512
V=(2048/3)pi
twice of that
Vbig=2*(2048/3)pi
Vbig=(4096/3)pi
find radius
(4096/3)pi=(4/3)pir^3
divide both sides by pi
(4096/3)=(4/3)r^3
times both sides by 3
4096=4r^3
divide both sides by 4
1024=r^3
cube root both sides
8∛2=r
aprox
10.0794
the answer you are looking for is 8∛2 or 10.0794in or something close to that
Answer:
6 511 104 in³
Step-by-step explanation:
Since we have 1 crate and 8 boxes fit into one crate.
So, volume of one crate, V' = 8 × volume of 1 box, V
Since the box is a rectangular prism of sides 2512 inches high, 18 inches long, and 18 inches wide, its volume, V = lwh where l = length of prism, h = height of prism and w = width of prism.
So, V = lwh = 18 in × 18 in × 2512 in = 813 888 in³
So, V' = 8 × 813 888 in³ = 6 511 104 in³
So, the minimum volume of the crate is 6 511 104 in³
