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jeka57 [31]
2 years ago
13

A pit was dug in the shape of a cuboid with a dimension 10m×8m×3m. The earth taken out is spread evenly on a rectangular plot of

land with dimension 40m × 30m. What is the increase in the level of the plot?
Mathematics
2 answers:
Aleks [24]2 years ago
6 0

hey buddy here is your answer!

Volume of a cuboid = l × b × h

Volume of earth dug out = 10 × 8 × 3 = 240 m^3

Volume of earh dug = 40 × 30 × height of the rectangular plot

240 = 40 × 30 × h

240 = 1200 × h

240 = 1200h

h = 240 / 1200 = 20 / 100 = 1 / 5 = 0.2

h = 0.2 m

So the plot height increased by 0.2 m or 200cm.

Thepotemich [5.8K]2 years ago
6 0
First we find the volume of the pit so 10*8*3 which is 240m^3
then we need the area of the plot which is 40*30=1200m^2
now we need to find out how many times 1200 goes into 240 to see how many meters it’s increased by (it will be less than 1)
we can put this as a fraction so 240/1200
1/5
0.2m increase
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To account for both initial conditions, take the derivative of y(x), thus, y'(x)=3C_1e^{3x}+C_2e^{3x}+3C_2xe^{3x}

Now, we can create our system of equations given our initial conditions:

y(x)=C_1e^{3x}+C_2xe^{3x}\\ \\y(0)=C_1e^{3(0)}+\frac{C_2}{6}(0)e^{3(0)}=0\\ \\C_1=0

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We then solve the system of equations, which becomes easy since we already know that C_1=0:

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Thus, our final solution is:

y(x)=C_1e^{3x}+C_2xe^{3x}\\\\y(x)=2xe^{3x}

3 0
2 years ago
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I hope this helped! :D

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5 0
3 years ago
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