Number 2 is 4x^5/3y^5 and 14 is 3125x^10
The thousands place (1000) is the fourth number to the left of the decimal, so round that one either up or down based on the number just one spot closer to the decimal, in this case, the hundreds place (100).
so we have 32,420
we can ignore the numbers that are going to become zeros as a result of the rounding . .
32,400
let's round 32,XXX either up or down based on the value in the hundreds place. if that value is 5 or greater, than we round up. if it is less than 5, than we round down.
4 is in the hundreds place, so we round down
32,000 is the answer
Iván used to measure the catsup the same as those given
Answer:

Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:

So:

Answer:
C. 20 feet
Step-by-step explanation:
Let x = width
Let y = length
If the length is at least 10 feet longer than the width:
⇒ x + 10 ≤ y
⇒ x ≤ y - 10
If the perimeter is to be no more than 100 ft:
⇒ 2x + 2y ≤ 100
⇒ x + y ≤ 50
⇒ x ≤ 50 - y
Equate the equations for x and solve for y:
⇒ y - 10 = 50 - y
⇒ 2y = 60
⇒ y = 30
Substitute found value of y into one of the inequalities for x:
⇒ x ≤ 30 - 10
⇒ x ≤ 20
Therefore, the maximum possible width of the fence is 20 feet.