Solve the system using elimination
y=-3x+6
y=x^2-4
1 answer:
Mutiply first equation by -1 and add to 2nd
-y=3x-6
<u>y=x^2-4 +</u>
0=x^2+3x-10
factor like any equation
what 2 numbers multiply to -10 and add to 3
-2 and 5
0=(x-2)(x+5)
set to zero
x-2=0
x=2
x+5=0
x=-5
solve for y in each case
for x=2
y=2^2-4
y=4-4
y=0
(2,0) is a point
for x=-5
y=(-5)^2-4
y=25-4
y=21
(-5,21) is another
the solutions are
(2,0) and
(-5,21)
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