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3 years ago

(3x^2-5x-7x^4)-(-2x^3+6x^4-5x^2)

Mathematics

2 answers:

Olenka [21]3 years ago

8 0

Answer:

-13x^4+2x^3+8x^2-5x

Step-by-step explanation:

(3x^2-5x-7x^4)-(-2x^3+6x^4-5x^2)

= 3x^2-5x-7x^4+2x^3-6x^4+5x^2

= -13x^4+2x^3+8x^2-5x

My name is Ann [436]3 years ago

5 0

Answer:

-x(13x³ - 2x² - 8x + 5)

Step-by-step explanation:

1. Distribute the negative to the numbers inside the parenthesis. Remember that two negatives multiplied will make a positive, and a negative and a positive will become a negative.

3x² - 5x - 7x^4 + 2x³ - 6x^4 + 5x²

2. Combine like terms. Remember that only numbers with the same number and exponents can be combined.

3x² - 5x - 7x^4 + 2x³ - 6x^4 + 5x²

↓

8x² - 5x - 7x^4 + 2x³ - 6x^4

↓

8x² - 5x - 13x^4 + 2x³

3. Rewrite the answer in descending order of powers.

-13x^4 + 2x³ + 8x² - 5x

4. Simplify The equation. The terms all have x in common, so we will take that out first. The smallest amount of x's any term has is one (-5x only has one x), so the most we can take out is one x. We will do this by lowering the power of every x by one.

x(-13x³ + 2x² + 8x - 5)

5. Since 13 and 5 are prime and do not go into 2 or 8 we will not be simplifying the coefficients. However, the last thing we can do is take out a negative.

-x(13x³ - 2x² - 8x + 5)

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