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3 years ago

L'shanda rode her bike 2.5 miles. Shaman rode her bike 3 miles. How many more feet did shanay rode her bike than l'shanda

Mathematics

2 answers:

vodka [1.7K]3 years ago

7 0

Im pretty sure its 0.5 i am not sure

9966 [12]3 years ago

6 0

3 - 2.5 = 0.5

shanay rode 1/2 a mile more

hope this helps :)

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What formula is used to determine which fraction is the larger one

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3 years ago

Is there a proportional relationship? A salt water solution for and aquarium calls for 35 parts of salt to 1000 parts of water t

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To check proportionality :

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2 years ago

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3 years ago

Read 2 more answers

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

Please help me ASAP

Serggg [28]

The class 4S because you divide each number by its mean mark and standard division and 4S is the highest.

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2 years ago