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2 years ago

8

CAN SOMONE PLEASE HELP ME OFFERING BRAINLYIST THINGG Determine the range of the function.

2 answers:

forsale [732]2 years ago

8 0

Answer:

(0,-5)

(1,-4.75)

(2,-4)

(3,-2.75)

(4,-1)

Step-by-step explanation:

Y=1/4x^2-5

1/4(0)^2-5= -5

1/4(1)^2-5= -4.75

1/4(2)^2-5= -4

1/4(3)^2-5= -2.75

1/4(4)^2-5= -1

KonstantinChe [14]2 years ago

7 0

The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain. In plain English, the definition means: The range is the resulting y-values we get after substituting all the possible x-values

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What is the domain of the function;<br> y= (x-1)2 -2

valkas [14]

It should be 2 but i’m not positive

5 0

3 years ago

If the altitude is √7, find the volume. 36√7 cu. units 18√7 cu. units 12√7 cu. units

rosijanka [135]

Answer:

$Volume = 12\sqrt{7}$ cubic units

Step-by-step explanation:

Volume of the square pyramid is given as ⅓*area of base*height of pyramid.

Where,

Area of base = 6*6 = 36

Height of pyramid = altitude = $\sqrt{7}$ units

Plug the values into the formula to find volume.

$Volume = \frac{1}{3}*36*\sqrt{7}$

$Volume = 12*\sqrt{7}$

$Volume = 12\sqrt{7}$ cubic units

8 0

2 years ago

Plz help I'm just having a brain fart right now<br><br>

Wittaler [7]

Answer:

x=11

Step-by-step explanation:

For extra help the second answer is: 7a(3-a)

4 0

3 years ago

Does anyone know this answer? If you do can someone help me please!

ira [324]

The answer’s c, y=5/2x+10

5 0

3 years ago

Help please n ty :P<br> sdhgfahedgewkgfzndb

Ugo [173]

Answer:

$y=-3.2\\\\y=-2.2\\\\y=-1.8$

Step-by-step explanation:

Insert the given x values for the given equation to find the corresponding y coordinate:

$y=0.2x-2$

$x:-6,-1,1$

Insert -6:

$y=0.2(-6)-2$

Simplify multiplication (when multiplying a negative and a positive, the result will always be negative):

$y=-1.2-2$

Simplify (when subtracting from a negative number, add the values, but keep the negative symbol):

$y=-3.2$

Insert -1:

$y=0.2(-1)-2\\\\y=-0.2-2\\\\y=-2.2$

Insert 1:

$y=0.2(1)-2\\\\y=0.2-2\\\\y=-1.8$

:Done

3 0

2 years ago