2 years ago

Choose the correct simplification of the expression d3 ⋅ d5.

Mathematics

1 answer:

snow_tiger [21]2 years ago

5 0

$d^3*d^5=d^{3+5}=d^8$

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How many solutions does the following equation have? − 4 ( x + 5 ) = − 4 x − 20 −4(x+5)=−4x−2

Svetach [21]

Answer:

-4x - 20= -4x - 20

Step-by-step explanation:

Multiply -4 and x and -4 and 5. It has infinite solutions

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2 years ago

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

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3 years ago

72.4 divided by 4 please help!!!!

wariber [46]

Answer:

18.1

hope it helps mate

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2 years ago

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OLga [1]

9 rows and 9 columns

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2 years ago

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Factor 24 p + 64 <br><br> Find "m"<br> m+8=22

rusak2 [61]

$24=8\cdot3;\ 64=8\cdot8\\\\24p+64=8\cdot3p+8\cdot8=\boxed{8(3p+8)}\\========================\\m+8=22\ \ \ |subtract\ 8\ from\ both\ sides\\\\m+8-8=22-8\\\\\boxed{m=14}$

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2 years ago