5 + 4 - 1 = 7
7 + 4 - 1 = 10
10 + 4 - 1 = 13
And so on
Answer:
y = 6cos(π/2)t
Step-by-step explanation:
Given in the question that,
in a simple harmonic motion in which
at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.
And,
the period is given as 4 sec
We know that model equation of simple harmonic motion is
<h3>y = a. cosb(t + c) + d</h3>
here,
a is amplitude
c is Horizontal shift or phase shift
d is Vertical shift
<h3>Step1</h3><h3>Find b</h3>
Period = 2 π / b
4 = 2π / b
b = 2π/4
b = 1π/2
<h3>Step2</h3><h3>Find shifts</h3>
Horizontal and vertical shifts are 0.
So, c = 0 and d = 0
<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>
y = 6cos π/2 (t + 0) + 0
y = 6cos(π/2)t
Answer:
x=2, y=-2
(2, -2)
Step-by-step explanation:
x + y = 0
3x - 2y = 10
3x - 2(0 - x) = 10 ( 2(0 - x) = -2x )
3x - (-2x) = 10 ( y = -x )
3x + 2x = 10
5x = 10
x = 2
Hope i helped, feel free to ask questions :D
Have a good day!
Check the picture below.
Make sure your calculator is in Degree mode.
62 (1178/19) is the answer.
