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3 years ago

-3 1/2 = - 1 1/4b what is b

Mathematics

1 answer:

Svetllana [295]3 years ago

8 0

Answer:

14/11

Step-by-step explanation:

Put the 3 into the one half by multiplying the 3 by the denominator. So now you have -7/2.

Then, make a common denomitator of 4, so you multiply top and bottom of fraction by 2 to get -14/4

Then, divide both sides of the equation by -11/4, and to do this, just multiply by the reciprocal of -4/11

-14/4 x -4/11 = 56/44

Simplify and get 14/11

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A polygon has its vertices at the following points.

seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

$\sqrt{(x2-x1)^2 + (y2 -y1)^2}$

AB = $\sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}$

BC = |7-4| = 3

CD = $\sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}$

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0

2 years ago

How does the 2 in the hundredths place compare to the 2 in the thousandths place?

dybincka [34]

Answer:

2 in the hundredths place is greater

Step-by-step explanation:

2 in the hundredths place is 10 times the thousands place

7 0

3 years ago

A man retires at age 50 with $605,000 in savings. He spends his savings at a steady rate, and after 6 years of retirement, he ha

givi [52]

Since it states that he "spends his savings at a steady rate," we can assume this is a linear equation.

What we know is that he started with $605,000 and after 6 years, he used $300,000. So, we just subtract what he had originally by what he used and get $305,000. We can now make the equation as follows:

300,000=6x, where x is the amount of money he spent in one year. This equation simplifies to x=50,000, which is the amount of money he spent in one year.

Since the question asks us to tell how long it will take him to reach $100,000 in savings, we can make the equation using previous value we have found:

100,000=305,000-50,000x, where x is the number of years passed.

So, this equation solves to -205,000=-50,000x, or x=4.1

I'm not sure how you want to express your answer, but it took him 4.1 years on top of the 6 years already passed to reach $100,000. This mean 10.1 years in total.

Hope this helps!

7 0

3 years ago

A line passes through the two given points. Is it vertical, horizontal, or neither?

Leviafan [203]

Answer:

A line passes through the two given points (5,2), (5,-2). The line is vertical line

Solution:

Given, two points are (5, 2) and (5, -2)

We have to find that a line that passes through the given two points is vertical or horizontal or neither.

First let us find the slope of the line that passes through given two points.

So, slope of line m $=\frac{y_{2}-y_{1}}{x_{2}-x_{2}} \text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

So slope of our line $=\frac{-2-2}{5-5}=\frac{-4}{0}$ = undefined

Here slope of our line is undefined which means it is parallel to the y – axis.

Hence, line passing through given points is vertical line

6 0

3 years ago

The height of a tree in feet over x years is modeled by the function f(x). f(x)=301+29e−0.5x which statements are true about the

Karo-lina-s [1.5K]

Given this equation:

$f(x)=301+29^{-0.5x}$

That represents the height of a tree in feet over (x) years. Let's analyze each statement according to figure 1 that shows the graph of this equation.

The tree's maximum height is limited to 30 ft.

As shown in figure below, the tree is not limited, so this statement is false.

The tree is initially 2 ft tall

The tree was planted in x = 0, so evaluating the function for this value, we have:

 $f(0)=301+29^{-0.5(0)}=301+1=302ft$

So, the tree is initially $\boxed{302ft}$ tall.

Therefore this statement is false.

Between the 5th and 7th years, the tree grows approximately 7 ft.

if x = 5 then:

 $f(5)=301+29^{-0.5(5)}=301ft$ 

if x = 7 then:

$f(7)=301+29e^{0.5(7)}=301ft$

So, between the 5th and 7th years the height of the tree remains constant
:
$\Delta=f(7)-f(5)=301-301=0ft$

This is also a false statement.

After growing 15 ft, the tree's rate of growth decreases.

It is reasonable to think that the height of this tree finally will be 301ft. Why? well, if x grows without bound, then the term $29^{-\infty}$ approaches zero.

Therefore this statement is also false.

Conclusion: After being planted this tree won't grow.

4 0

3 years ago

Read 2 more answers