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3 years ago

Determine the product, h (x), of the linear and quadratic factors.

Mathematics

1 answer:

Wewaii [24]3 years ago

8 0

$h(x) =8x^3-19x^2+14x-3$

Step-by-step explanation:

Given functions are:

$f(x) = 8x-3\\g(x) = (x-1)^2$

h(x) is the product of g(x) and f(x)

$h(x) = f(x) * g(x)\\= (8x-3)(x-1)^2\\= (8x-3)(x^2-2x+1)\\= 8x(x^2-2x+1)-3(x^2-2x+1)\\= 8x^3-16x^2+8x-3x^2+6x-3$

Combining like terms

$=8x^3-16x^2-3x^2+8x+6x-3\\=8x^3-19x^2+14x-3$

Hence,

$h(x) =8x^3-19x^2+14x-3$

Keywords: Functions, product

Learn more about functions at:

#LearnwithBrainly

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