Answer:
A. {u1,u2,u3,u4} is a linearly independent set of vectors unless one of {u1,u2,u3} is the zero vector.
Step-by-step explanation:
Given that u4 is not a linear combination of {u1,u2,u3}
This means there is no possibility to write u4 = au1+bu2+cu3 for three scalars a,b,and c.
This gives that 
This implies that these four vectors are not linearly dependent but linearly independent.
Hence option a is right.
A. {u1,u2,u3,u4} is a linearly independent set of vectors unless one of {u1,u2,u3} is the zero vector.
The answer is 70 70 70 70 70 70 seventy seventy
Answer:
x/5+9
Step-by-step explanation:
Check the picture below.
the surface area of the pyramid is simply the area of the four triangular faces plus the squarish base, and the triangular faces have a base of 12 and an altitude or height of "s", and we know that's 336.
![336~~ = ~~\stackrel{\textit{\LARGE Areas}}{\stackrel{square}{(12)(12)}~~ + ~~\stackrel{\textit{four triangles}}{4\left[ \cfrac{1}{2}(\underset{b}{12})(\underset{h}{s}) \right]}}\implies 336~~ = ~~144~~ + ~~24s \\\\\\ 192=24s\implies \cfrac{192}{24}=s\implies 8~m=s](https://tex.z-dn.net/?f=336~~%20%3D%20~~%5Cstackrel%7B%5Ctextit%7B%5CLARGE%20Areas%7D%7D%7B%5Cstackrel%7Bsquare%7D%7B%2812%29%2812%29%7D~~%20%2B%20~~%5Cstackrel%7B%5Ctextit%7Bfour%20triangles%7D%7D%7B4%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cunderset%7Bb%7D%7B12%7D%29%28%5Cunderset%7Bh%7D%7Bs%7D%29%20%5Cright%5D%7D%7D%5Cimplies%20336~~%20%3D%20~~144~~%20%2B%20~~24s%20%5C%5C%5C%5C%5C%5C%20192%3D24s%5Cimplies%20%5Ccfrac%7B192%7D%7B24%7D%3Ds%5Cimplies%208~m%3Ds)
Because you have an percentage, you have to move two decimal places to the front, you'll get .34 and multiply it by 66. Finally, your final answer is 22.44