We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2

$6C2= \frac{6!}{2!*4!} \\ \\ 
= \frac{6*5}{2} \\ \\ 
=15$

This means, there can be 15 different combinations of 2 members that can sit in the front row.

So, the answer to this question is option A

6 0

3 years ago

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What is the solution of -(x + 1) - 5 > 10

Pie

-(x + 1) - 5 > 10
-x - 1 - 5 > 10
- x - 6 > 10
Add 6 to the both sides,
-x - 6 + 6 > 10 + 6
-x > 16
x < -16 [ changed sign 'cause changed -sign ]

In short, Your Answer would be x < -16

Hope this helps!

6 0

3 years ago

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Cole says that all quadrilaterals are polygons but not all polygons are quadrilaterals is he correct explain��

zepelin [54]

YES, this is correct. All quadrilaterals whether is a trapezoid, parallelogram, rhombus and others, they are all polygons and all they have 4 sides and 4 angles. We know that a polygon is a figure with at least three sides and three angles.

Not all polygons are quadrilateral, this is also correct since some polygons have five or more sides and angles.

7 0

3 years ago