All categories

2 years ago

PLEASE HELPP!!!

Mathematics

1 answer:

jarptica [38.1K]2 years ago

5 0

Answer:

Reason 4. Division Property of Equality

Step-by-step explanation:

It should be Multiplication Property of Equality instead, which is:

If given a = b

then a × c = b × c

You might be interested in

Alex purchased a seven-year $600 bond at par value with a 5% coupon. What is the total value of the coupons?

anyanavicka [17]

Answer

300 dollars

because u do 600x.5

4 0

2 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

2 years ago

Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS

olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....$

where, n = number of trials (samples) taken = 36 couples

r = number of success

p = probability of success which in our question is probability

of a girl, i.e.; p = 0.5

Let X = Numbers of girls in groups of 36 births

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

Mean, E(X) = $n \times p$ = $36 \times 0.5$ = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

Standard deviation, S.D.(X) = $\sqrt{n\times p\times (1-p)}$

= $\sqrt{36\times 0.5\times (1-0.5)}$

= 3

3 0

2 years ago

Consider this three digit sequence 943. Is the first digit the largest or the second digit the smallest, and, is the third digit

maw [93]

Well, 9 is the largest, but 4 is the smallest and 3 is the second odd number. So it would go yes, no, no or if it's just one question, it would be no.

3 0

2 years ago

Which pipe configuration can deliver more water to

Stels [109]

Answer: One 8-cm pipe (Its is greater than the total area of of two 4-cm pipes)

Step-by-step explanation:

The area of a circle can be calculate with this formula:

$A=\pi r^2$

Where "r" is the radius of the circle.

We need to calculate the area of 8-cm pipe. In this case:

$r=8cm$

Then, substituting the radius into the formula, we get:

$A=\pi (8cm)^2\\\\A=201.06cm^2$

Now we must calculate the area of the two 4-cm pipes.

Since they are two pipes, the formula is:

$A=2\pi r^2$

In this case:

$r=4cm$

Then, substituting into the formula, we get:

$A=2\pi (4cm)^2\\\\A=100.53cm^2$

Therefore, since the area of one 8-cm pipe is greater than the total area of of two 4-cm pipes, we conclude that the pipe configuration that can deliver more water to residents is:

One 8-cm pipe

4 0

3 years ago