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Karo-lina-s [1.5K]
2 years ago
7

Please, Help.the answer isn't 30°

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
8 0

The <em>missing</em> angle of the <em>right</em> triangle ABC has a measure of 30°. (Correct answer: A)

<h3>How to find a missing angle by triangle properties</h3>

Triangles are <em>geometrical</em> figures formed by three sides and whose sum of <em>internal</em> angles equals 180°. There are two kind of triangles existing in this question: (i) <em>Right</em> triangles, (ii) <em>Isosceles</em> triangles.

<em>Right</em> triangles are triangles which one of its angles equals 90° and <em>isosceles</em> triangles are triangles which two of its sides have <em>equal</em> measures.

According to the statement, we know that triangle BQR is an <em>isosceles</em> triangle, whereas triangles ABC, ANB and NBC are <em>right</em> triangles. Based on the figure attached below, we have the following system of <em>linear</em> equations based on <em>right</em> triangles ABC and NBC:

<em>2 · x + 90 + θ = 180</em>   (1)

<em>(90 - x) + 90 + θ = 180</em>   (2)

By equalizing (1) and (2) we solve the system for <em>x</em>:

<em>2 · x = 90 - x</em>

<em>3 · x = 90</em>

<em>x = 30</em>

And by (1) we solve the system for <em>θ</em>:

<em>θ = 180 - 2 · x - 90</em>

<em>θ = 30</em>

<em />

The <em>missing</em> angle of the <em>right</em> triangle ABC has a measure of 30°. (Correct answer: A) \blacksquare

To learn more on right triangles, we kindly invite to check this verified question: brainly.com/question/6322314

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One angle of the following triangle measures 2x. How many degrees does that angle
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<u>Given</u><u> info</u><u>:</u><u>-</u> In triangle (∆)ABC , in which ∠A = 2x, ∠B = x+15° and ∠C = 2x + 10°. Then find the value of x , also find the measure of each angles of a triangle.

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Let the angles be 2x, x+15 and 2x+10 respectively.

∵ Sum of the three angles of a triangle is 180°

∴ ∠A + ∠B + ∠C = 180° [Sum of ∠s of a ∆=180°]

→2x + x+15 + 2x+10 = 180°

→ 2x + x + 2x + 15 + 10 = 180°

→ 3x + 2x + 15 + 10 = 180°

→ 5x + 15 + 10 = 180°

→ 5x + 25 = 180°

→ 5x = 180°-25

→ 5x = 155°

→ x = 155°÷5 = 155/5 = 31.

Now, finding the measure of each angles of a ∆ABC by putting the original value of “x”.

∴ ∠A = 2x = 2(31) = 62°

∠B = x+15 = 31 + 15 = 46°

∠C = 2x + 10 = 2(31) + 10 = 62 + 10 = 72°.

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