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seraphim [82]
3 years ago
15

Factor the expression shown below completely.

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

D. 2(3x - 5)²

Step-by-step explanation:

18x² - 60x + 50

The expression can be factorize as follows;

18x² - 60x + 50

divide through by 2

2(9x² - 30x + 25)

The bracket equation can be factorized further

Find the square value that can be multiplied to get 9x² and 25

The values are 3x and 5

2( (3x- 5)(3x - 5) )

2(3x - 5)²

alexira [117]3 years ago
3 0

Answer:D. 2(3x-5)^2

Step-by-step explanation:

18x^2-60x+50=2(9x^2-30x+25)

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A store employee conducted a survey of 390 randomly selected customers. According to the survey, 180 of the customers often use
shusha [124]
You do 390/100 = 180/x then 390×X=390X
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Simplify 3(2m^3n^-2)^4
Effectus [21]

Answer:

(48 m^12)/n^8

Step-by-step explanation:

Simplify the following:

3 ((2 m^3)/(n^2))^4

Multiply each exponent in (2 m^3)/(n^2) by 4:

3×2^4 m^(4×3) n^(-2×4)

4 (-2) = -8:

3×2^4 m^(4×3) n^(-8)

4×3 = 12:

(3×2^4 m^12)/(n^8)

2^4 = (2^2)^2:

(3 (2^2)^2 m^12)/(n^8)

2^2 = 4:

(3×4^2 m^12)/(n^8)

4^2 = 16:

(3×16 m^12)/(n^8)

3×16 = 48:

Answer: (48 m^12)/n^8

5 0
3 years ago
F(x) = -322 Find f(-2)​
serg [7]

Answer:

f ( - 2 ) =  - 12

Step-by-step explanation:

f ( - 2 ) = - 3 ( -2 )^2

then you do the exponent first so

- 3 ( 4 )

now you multpily the - 3 and 4

you get - 12

8 0
2 years ago
The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

r=10/2=5\ units ---> the radius is half the diameter

A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

A=25\pi-16\pi+9\pi-4\pi+\pi

A=15\pi\ units^2

7 0
3 years ago
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