Jane will roll a number cube 30 times.How many times would Jane expect to roll a number larger than 4?

Mathematics

1 answer:

Naily [24]3 years ago

8 0

Answer:

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Step-by-step explanation:

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Joy is giving ice cream cones to some children at a carnival. She has 8 chocolate ice cream cones, 10 vanilla ice cream cones, a

AlladinOne [14]

It would be 8 over 24 plus 10 over 23. : )

5 0

3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

Two students are preparing for a marathon. Hector ran 8 miles in 85 minutes. Mario ran 6 miles in 55 minutes. Who has the faster

Stels [109]

$formula\ for\ average\ speed= \frac{distance}{time}\\\\
Hector:\\\\
v_H=\frac{8miles}{85\ minutes}\approx0,09\frac{mile}{min}\\\\
Mario:\\\\
v_M=\frac{6miles}{55minutes}=0,1\frac{miles}{min}\\\\
Mario\ has\ faster\ speed.$