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2 years ago

3.47472 rounded to the nearest 10th

Mathematics

2 answers:

Neporo4naja [7]2 years ago

8 0

Answer:

It would be 0 its nowhere near a ten

Step-by-step explanation:

hope i helped

ser-zykov [4K]2 years ago

5 0

Good evening ,

______

Answer:

3.5

___________________

Step-by-step explanation:

the number that comes after the comma is called the 10th

In our case is 4

We look at the 100th which is 7 and because 7 ≥ 5

then our number rounded to nearest 10th is : 3.5

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Remove the brackets and simplify

Komok [63]

Answer:

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How much should you invest at 4% simple interest in order to earn $50 interest in 6 months

LenaWriter [7]

Simple interest formula
Interest = Pit = $50
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i=annual interest rate = 0.04
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2 years ago

The roots of the equation 3x²-2x-4=0 are J and K. Evaluate J² + K².

melamori03 [73]

Answer:

28/9

Step-by-step explanation:

If the roots are J and K, then:

3 (x − J) (x − K) = 0

3 (x² − (J+K)x + JK) = 0

So if we factor out the leading coefficient:

3x² − 2x − 4 = 0

3(x² − 2/3x − 4/3) = 0

The coefficient of the second term is the sum of the roots:

J + K = 2/3

And the constant is the product of the roots:

JK = -4/3

If we take the sum of the roots and square it:

(J + K)² = (2/3)²

J² + 2JK + K² = 4/9

And subtract twice the product:

J² + K² = 4/9 − 2JK

J² + K² = 4/9 − 2(-4/3)

J² + K² = 4/9 + 8/3

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3 years ago

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3 years ago

A sociologist develops a test to measure attitudes towards public transportation, and 27 randomly selected subjects are given th

taurus [48]

Answer:

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0518