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2 years ago

3.47472 rounded to the nearest 10th

Mathematics

2 answers:

Neporo4naja [7]2 years ago

8 0

Answer:

It would be 0 its nowhere near a ten

Step-by-step explanation:

hope i helped

ser-zykov [4K]2 years ago

5 0

Good evening ,

______

Answer:

3.5

___________________

Step-by-step explanation:

the number that comes after the comma is called the 10th

In our case is 4

We look at the 100th which is 7 and because 7 ≥ 5

then our number rounded to nearest 10th is : 3.5

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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x

natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

P(a < X < b) = $\int_{a}^{b} \frac{2}{x^{3}} dx$ = $2\int_{a}^{b} x^{-3} dx$

= $2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx$ { Because $\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a$ }

= $2[ \frac{x^{-2} }{-2}]^{b}_a$ = $\frac{2}{-2} [ x^{-2} ]^{b}_a$

= $-1 [ b^{-2} - a^{-2} ]$ = $\frac{1}{a^{2} } - \frac{1}{b^{2} }$

a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }

Comparing with general probability we get,

P(1 < X < 5) = $\frac{1}{1^{2} } - \frac{1}{5^{2} }$ = $1 - \frac{1}{25}$ = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/ $8^{2}$ - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = $\frac{1}{6^{2} } - \frac{1}{10^{2} }$ = $\frac{1}{36} - \frac{1}{100 }$ = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

= $(\frac{1}{1^{2} } - \frac{1}{6^{2} })$ + (1/ $10^{2}$ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

⇒ P(1 < X < x) = 0.75

⇒ $\frac{1}{1^{2} } - \frac{1}{x^{2} }$ = 0.75

⇒ $\frac{1} {x^{2} }$ = 1 - 0.75 = 0.25

⇒ $x^{2}$ = $\frac{1}{0.25}$ ⇒ $x^{2}$ = 4 ⇒ x = $2$

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0

2 years ago

The label on a package of bolts says each bolt has a diameter of 0.35 inch. To be in the package, the percent error of the diame

qaws [65]

Answer: No

Step-by-step explanation:-

Labeled diameter on the bolt = 0.35 inch

The observed diameter of the bolt= 0.33 inch

${\text {Percentage Error}}=|\frac{\text {labeled value}-{Observed value}}{\text {Observed value}}|\times 100\%$

${\text{Percentage Error}=|\frac{0.35-0.33}{0.33}|\times 100\%=6.06\%$

For the bolt to be in the package, the percent error must be less than 5%. As the percent error is 6.06% which is greater than 5%, the bolt cannot be in the package.

7 0

3 years ago

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Find an explicit rule for the nth term of the sequence.

taurus [48]

Answer: -4 . 2ⁿ⁻¹

Step-by-step explanation: This is a geometric progression

the nth term is given by arⁿ⁻¹

a = the first term of the sequence

r = common ratio

n= number of terms

for this sequence

a = -4

r = -8/-4 = 2

nth term, an = -4 . 2ⁿ⁻¹

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Eduardwww [97]

Answer:

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