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Natali5045456 [20]
3 years ago
14

Evaluate 6(p-q)/(p-1) when p=13 and q=3

Mathematics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

Its a i just took the test

Step-by-step explanation:

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(-8,5)  (-3,10) [Use the y1-y2 over x1-x2 formula to solve for slope]

10 - 5         5
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Hurray! You got a slope of one. Now substitute this back into your original equation:
y=mx+b --> y=1x+b 

Next, we find what our "b" is, or what our y-intercept is:
Using one of the previous points given, substitute them into the new equation:
[I used the point (-3, 10) ]

y=1x+b
10=1(-3)+b  SUBSTITUTE 
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So, now we have our y-intercept. Use this and plug it into the equation:
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y=1x+13 is our final answer.



5) So for perpendicular lines, your slope will be the opposite reciprocal of the original slope. (Ex: Slope is 2, but perpendicular slope is -1/2) 

We have the equation y= 3x-1, so find the reciprocal slope! 
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Good! Now we take our given point, (9, -4) and plug it into the new equation:

y=-1/3x-1
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--------
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So, our final answer is y=-1/3x+(-1)

6) I don't know, sorry! :( 
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Step-by-step explanation:


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Answer:

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